Aufgabe 2

clear all;
u = 1.6605e-27
u = 1.6605e-27
c = 299792458
c = 299792458
e = 1.609e-19
e = 1.6090e-19
r0 = 1.3e-15
r0 = 1.3000e-15
NA = 6.02214086e23
NA = 6.0221e+23

a)

Nrel = 0.533
Nrel = 0.5330
tHalbC = 5730 %Jahre 
tHalbC = 5730
t = - tHalbC / log(2) * log(Nrel)
t = 5.2017e+03

b)

A = 1.81e8 %pro Jahr
A = 181000000
mC12 = 0.030
mC12 = 0.0300
mC12mol = 0.012
mC12mol = 0.0120
c14Rel = 1e-12
c14Rel = 1.0000e-12
NC14 = A * tHalbC / log(2)
NC14 = 1.4963e+12
NC12 = mC12 / mC12mol * NA
NC12 = 1.5055e+24
N0C14 = NC12 * c14Rel
N0C14 = 1.5055e+12
t = -tHalbC /log(2) * log(NC14 / N0C14)
t = 51.0734

c)

t = - tHalbC / log(2) * log(1e-3)
t = 5.7104e+04