Aufgabe 4
clear
all
;
e = 1.602e-19;
h = 6.626e-34;
me = 9.11e-31;
c = 299792458
c = 299792458
Gegeben:
b = 0.08e-9
b = 8.0000e-11
E = @(n) h^2 * n.^2 / (8*me*b^2)
E =
function_handle with value:
@(n)h^2*n.^2/(8*me*b^2)
a) Energieniveaus und Wellenlängen
n = (1:5)
n =
1×5
1 2 3 4 5
En = E(n)
En =
1×5
10
-15
×
0.0094 0.0377 0.0847 0.1506 0.2353
En_ev = En / e
En_ev =
1×5
10
3
×
0.0588 0.2350 0.5288 0.9401 1.4689
lambda = h*c ./ En
lambda =
1×5
10
-7
×
0.2110 0.0528 0.0234 0.0132 0.0084
b) Übergangsfrequenzen
E53 = En(5) - En(3);
E53_eV = E53 / e
E53_eV = 940.0955
f53 = E53 / h
f53 = 2.2729e+17
E31 = En(3) - En(1);
E31_eV = E31 / e
E31_eV = 470.0478
f31 = E31 /h
f31 = 1.1365e+17
E41 = En(4) - En(1);
E41_eV = E41 / e
E41_eV = 881.3396
f41 = E41 / h
f41 = 2.1309e+17