Aufgabe 4
h = 1;
%m
d = 0.6;
%m
dZ = 0.004;
lZ = 0.15;
g = 9.81
g = 9.8100
V = 500;
%ml
N = 10;
eta = 0.001;
%Pa s
rho = 1e3;
%kg/m^3
Abgeleitete Größen
r = dZ/2
r = 0.0020
A = pi*r^2
A = 1.2566e-05
a)
pB = rho*h*g
%Pa
pB = 9810
Vdot = (pi*r^4)/(8*eta*lZ) * pB
%m^3 / s
Vdot = 4.1092e-04
VdotMl = Vdot * 1e6
VdotMl = 410.9203
deltaT = N*V/VdotMl
%s
deltaT = 12.1678
b)
v = Vdot / A
v = 32.7000
c)
nr = nthroot(2,4)
nr = 1.1892
r2 = nr*r
r2 = 0.0024