Aufgabe 2
rho_Eiche = 671
rho_Eiche = 671
alpha = 5
alpha = 5
h = 35
h = 35
r = 1.41
r = 1.4100
F = 330e3
F = 330000
g = 9.81;
Mastgewicht
m = r^2*pi*h*rho_Eiche
m = 1.4668e+05
m_t = m / 1e3
m_t = 146.6826
Drehmoment
F_N = sind(alpha) * m * g
F_N = 1.2541e+05
M = F_N * h/2
M = 2.1947e+06
Höhe zum Anbringen
hSeil = M / F + h/2
hSeil = 24.1507