Aufgabe 4

h = 10
h = 10
m = 200
m = 200
R_L = 12
R_L = 12
g = 9.81 %m/s^2
g = 9.8100

a)

h
h = 10

b)

ETop = m*g*2*R_L;
Epot = m*g*h;
EkinMin = ETop - Epot;
v = sqrt(2*EkinMin / m)
v = 16.5735
v_kmh = v * 3.6
v_kmh = 59.6645

c)

vTopMin = sqrt(g*R_L) %FZ = FG
vTopMin = 10.8499
Etop = m*g*2*R_L + 0.5*m*vTopMin^2;
Ekin0 = Etop - m*g*h;
vAnfang = sqrt(2*Ekin0 / m)
vAnfang = 19.8091

d)

F = 800;
vEnd = sqrt(2*Etop / m)
vEnd = 24.2611
a_B = F / m;
t = vEnd / a_B
t = 6.0653