Aufgabe 3

h = 12000 * 0.3048 %ft in m
h = 3.6576e+03
a = -9.81
a = -9.8100
hS = 4500 * 0.3048
hS = 1.3716e+03

Zeit bis Schirm

dh = -(h - hS);
tS = sqrt(2*dh/a)
tS = 21.5883

Endgeschwindigkeit

t = sqrt(-2*h/a)
t = 27.3073
v = a*t
v = -267.8845
vkmh = v*3.6
vkmh = -964.3842