Aufgabe 3

clear all;
%Konstante
s0 = 25e-2
s0 = 0.2500
%Gegeben
f = 5e-3
f = 0.0050
Vok = 10
Vok = 10

a)

fOk = s0/Vok
fOk = 0.0250

VGes = 400
VGes = 400
Vobj = VGes / Vok
Vobj = 40
t = f * Vobj
t = 0.2000

lBak = 6e-6
lBak = 6.0000e-06
Vobj = 100
Vobj = 100

tmp = 1/f - 1/(t + f)
tmp = 195.1220
g = tmp^(-1)
g = 0.0051
B = lBak*(t+f)/g
B = 2.4000e-04

lMegavir = 700e-9
lMegavir = 7.0000e-07
lambda = 490e-9
lambda = 4.9000e-07
n = 1.5
n = 1.5000
alpha = 60/2
alpha = 30

dmin = lambda/(n*sind(alpha))
dmin = 6.5333e-07
dmin < lMegavir
ans = logical
   1

lambda = 550e-9
lambda = 5.5000e-07

dMin = 0.61*lambda / (n*sind(alpha))
dMin = 4.4733e-07