Aufgabe 1
clear
all
;
k_B = 1.38064852e10-23
k_B = 1.3806e+10
R = 8.3144598
R = 8.3145
n = 1
%mol
n = 1
T = 300
%K
T = 300
V = 0.01
%m^3
V = 0.0100
c)
p = n*R*T
p = 2.4943e+03