Aufgabe 6
Gegeben:
clear all;
U0a = 5 %V
U0a = 5
U0b = 8 %V
U0b = 8
U0c = 7 %V
U0c = 7
R1 = 1 %Ohm
R1 = 1
R2 = 5 %Ohm
R2 = 5
R3 = 3.5 %Ohm
R3 = 3.5000
R4 = 2 %Ohm
R4 = 2
R5 = 0.3 %Ohm
R5 = 0.3000
R6 = 4.8 %Ohm
R6 = 4.8000
Stromstärke Kirchoff
Knoten: 
Masche 
: 
: Masche 
: 
: Gleichsetzen:
Rers45 = 1/sum(1./[R4 R5])
Rers45 = 0.2609
I3 = ((U0b - U0a)*(R3 + Rers45) + (U0c + U0b)*(R1 + R6))/((R3 + Rers45 + R2)*(R1 + R6) + R2*(R3+Rers45))
I3 = 1.4118
%Buch:
%I3 = ((-U0a)*(R3 + Rers45) + (U0c + U0b)*(R1 + R6))/((R3 + Rers45 + R2)*(R1 + R6) + R2*(R3+Rers45))
I1 = (I3*(R3 + Rers45 + R2) - U0c - U0b) / (R3 + Rers45)
I1 = -0.6998
I1_check = (U0b - U0a - R2*I3)/(R1 + R6)
I1_check = -0.6998
I2 = I1 - I3
I2 = -2.1115