Aufgabe 3

Gegeben:

clear all;
R = 440 %Ohm
R = 440
Ri = 0.2 %Ohm
Ri = 0.2000
I = 0.52 %A
I = 0.5200

Gesamtwiderstand

Rges = R + Ri
Rges = 440.2000

Leistung

Pges = Rges*I^2
Pges = 119.0301
Pi = Ri*I^2
Pi = 0.0541
PR = R*I^2
PR = 118.9760